PHP: daysBetween(date1, date2)

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HoboBen	Created : 26 November 2009 Edited : 27 November 2009 Language : Perl PHP: daysBetween(date1, date2)
\|edit\| Fixed, hopefully! \|edit\| function daysBetween($date1, $date2) returns an array of dates containing every day between $date1 and $date2 in YYYYMMDD format. <?php <?php /* * Updated 20091127 * * * * function daysBetween($date1, $date2) * * $date1: Start date in format YYYYMMDD * $date2: End date in format YYYYMMDD * * returns an array of dates containing every day between $date1 and $date2 * in YYYYMMDD format. * * * * function daysInMonth($month, $year) * * $month: month as integer * $year: year as integer * * returns an integer * * * * function isLeapYear($year) * * $year: year as integer * * returns a boolean * / // Example usage $d1 = 20080226; $d2 = 20080304; echo "<b>Days Between $d1 and $d2:</b><br /><br />"; $days = daysBetween($d1, $d2); foreach($days as $day) { echo "$day<br />"; } // Example usage - End function daysBetween($date1, $date2) { if ((strlen($date1) != 8) \|\| (strlen($date2) != 8)) { echo "Error: function daysBetween: dates must be given in YYYYMMDD format."; return array(); } if ($date1 > $date2) { $date1 ^= $date2 ^= $date1 ^= $date2; } if ($date1 == $date2) { return array($date1); } $y1 = substr($date1, 0, 4); $m1 = substr($date1, 4, 2); $d1 = substr($date1, 6, 2); $y2 = substr($date2, 0, 4); $m2 = substr($date2, 4, 2); $d2 = substr($date2, 6, 2); $y1 = ltrim($y1, '0'); $y2 = ltrim($y2, '0'); $m1 = ltrim($m1, '0'); $m2 = ltrim($m2, '0'); $d1 = ltrim($d1, '0'); $d2 = ltrim($d2, '0'); $result = array(); while ( (($y1 1000)+($m1 * 100)+$d1) <= (($y2 * 1000)+($m2 * 100)+$d2) ) { $result[] = ''. str_pad($y1, 4, "0", STR_PAD_LEFT). str_pad($m1, 2, "0", STR_PAD_LEFT). str_pad($d1, 2, "0", STR_PAD_LEFT); if($d1 == daysInMonth($m1, $y1)) { $d1 = 1; if($m1 == 12) { $m1 = 1; $y1++; } else { $m1++; } } else { $d1++; } } return $result; } function daysInMonth($month, $year) { if (isLeapYear($year)) { $feb = 29; } else { $feb = 28; } $months = array( 1=>31, 2=>$feb, 3=>31, 4=>30, 5=>31, 6=>30, 7=>31, 8=>31, 9=>30, 10=>31, 11=>30, 12=>31 ); return $months[$month]; } function isLeapYear($year) { return ( (($year % 4 == 0) & ($year % 100 != 0)) \| ($year % 400 == 0) ); } ?> --v

Comments
Friday, 27 November 2009, 07:04
Jayenkai	function DaysBetween($Date1,$Date2) { $Date1_Timestamp=strtotime($Date1); $Date2_Timestamp=strtotime($Date2); $Between=$Date1_Timestamp-$Date2_Timestamp; if ($Date2_Timestamp>$Date1_Timestamp) {$Between=$Date2_Timestamp-$Date1_Timestamp;} $DaysInaTimestamp = 606024; // SecsMinsHours $Result=floor($Between/$DaysInaTimestamp); return $Result; } echo DaysBetween("Today","December 25th"); --v
Friday, 27 November 2009, 07:21
HoboBen	Haha, all right, that's quite simple! But it's not what my code does - it actually returns a list of all the days between these two dates, which I needed for my website analytics code. e.g. Days Between 20080226 and 20080304 20080226 20080227 20080228 20080229 20080301 20080302 20080303 20080304
Friday, 27 November 2009, 07:37
Jayenkai	Oh, ok.. Don't forget, then, that date("Ymd",mktime(0,0,0,$day,$mon,$year)) can do "More/Less" days than in the actual month. So (-10,9,2010) is the same as (22,8,2010) quicker!

PHP: daysBetween(date1, date2)

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