String problem!

-=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- (c) WidthPadding Industries 1987 0\|712\|0 -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=- -=+=-
Socoder -> On Topic -> String problem!
Sun, 04 Jan 2009, 04:31
Afr0	Aaargh! This is driving me nuts! I can't figure out this one issue! ... How would I go about finding the DisplayName parameter in an ILN command that looks like so: ILN trid status email@addr.ess networkid displayname clientid dpobj The problem is that DisplayName, obviously, can be of variable length and contain multiple spaces!! So one ILN command might look like: 'ILN 5 NLN afr088@hotmail.com HELLO I ARE TEH c00lzorz!!11 454564' While another one might look like: 'ILN 5 BSY test@msn.com TEST! 34634734' The MSNObject parameter is optional, but I can figure out where it starts in the string because it has a 'header' of '<msnobj'. Basically... how do I get only the DisplayName parameter as one single string from all this mess?! Here's some code I've been messing with: if (ILN.Contains("ILN")) { int Place = 0; string DecodedILN = HttpUtility.UrlDecode(ILN, Encoding.UTF8); string[] Params = DecodedILN.Split(' '); string Command = Params[0]; //Actual ILN command. string TransactionID = Params[1]; string StatusCode = Params[2]; string AccountName = Params[3]; //Place in string of DisplayName. //Add 3 to the end to account for spaces. Place = StatusCode.Length + AccountName.Length + Command.Length + TransactionID.Length + 3; string DisplayName = DecodedILN.Remove(0, Place); string ClientID = "33"; MSNContact Contact = new MSNContact(StatusCode, AccountName, DisplayName, long.Parse(ClientID)); if (DecodedILN.Contains("<msnobj")) { Place = DecodedILN.IndexOf("<msnobj ") - 1; string MSNObject = DecodedILN.Remove(0, Place); MessageBox.Show(MSNObject); } --v Edit: As you might be able to tell from this code, I am able to remove everything up to DisplayName, but I don't know how to remove what comes after it! Edit: I don't care if you write your answer in Blitz, Python or Malbolge! Just give me some ideas... please! -=-=- Afr0 Games Project Dollhouse on Github - Please fork!
Sun, 04 Jan 2009, 05:06
Jayenkai	ILN trid status "ILN 5 NLN" email@addr.ess "afr088@hotmail.com" networkid ? displayname "HELLO I ARE TEH c00lzorz!!11" clientid 454564 dpobj ? According to here... You're actually using the topmost "ILN" message type. The "MSNP14" is the one with the other two bits of info. Now, assuming you're only working with ILN, it's easy. The first few bits you know.. They're structured as they should be. The last bit is the ID number, everything inbetween is the person's name. Assume that, first.. You have "Left data", (What you can get already) "Possible Display Name" (the chunky middle bit) and "Right data" (last bit.) What you'll have to do, is figure out what format "dpobj" should be in, and check if "Right Bit" = "A client ID or a possible dpobj".. This'll help If it is a possible dpobj, then use Right Data as DPObj, and then take off the rightmost bit from "Possible Display Name" and assume that's the Client ID.. (should be a number!) Next, take the leftmost bit from "Possible Display Name" and assume that's network ID.. (should be a single digit, according to the link above) And whatever's left inside "Possible Display Name" will more than likely be the person's display name.. -=-=- ''Load, Next List!''
Sun, 04 Jan 2009, 09:10
Afr0	Hmmm, well, I did some testing and wrote this: private string Test(string StrData) { string ReturnStr = ""; string TmpStr = ""; for (int i = 0; i < StrData.Length - 8; i = i + 8) { TmpStr = StrData.Substring(i, 8); ReturnStr = ReturnStr + TmpStr; if (TmpStr.Equals(" <msnobj") \|\| TmpStr.Equals("<msnobj ")) break; } return ReturnStr.Replace("msnobj", ""); } --v It doesn't work very well. First of all it absolutely requires that the ILN command contains an MSN Object (DPObject - Display Picture Object), and it doesn't seem to return the data I want in 9 out of 10 cases because the TmpStr can be apparently have way too many values (I.E it could be '567 <ms' or '8 <msnob'). Jay, I'm not working with MSNP14. I'm working with MSNP9, which has the MSNObject, but not the NetworkID. MSN Objects were first introduced in MSNP9. -=-=- Afr0 Games Project Dollhouse on Github - Please fork!
Sun, 04 Jan 2009, 09:26
Jayenkai	Oh, ok.. I just googled the thing.. I haven't a clue what it is you're using um.. <shrugs> -=-=- ''Load, Next List!''
Sun, 04 Jan 2009, 09:47
Afr0	The MSNObject looks like: <msnobj Creator="buddy@hotmail.com" Size="24539" Type="3" Location="TFR2C.tmp" Friendly="AAA=" SHA1D="trC8SlFx2sWQxZMIBAWSEnXc8oQ=" SHA1C="U32o6bosZzluJq82eAtMpx5dIEI="/> --v Put that together with the ILN and you get: ILN 5 NLN afr088@hotmail.com HELLO I ARE TEH c00lzorz!!11 454564 <msnobj Creator="afr088@hotmail.com" Size="24539" Type="3" Location="TFR2C.tmp" Friendly="AAA=" SHA1D="trC8SlFx2sWQxZMIBAWSEnXc8oQ=" SHA1C="U32o6bosZzluJq82eAtMpx5dIEI="/> --v -=-=- Afr0 Games Project Dollhouse on Github - Please fork!
Sun, 04 Jan 2009, 10:03
Scherererer	Why don't you work backwards: find the part that says <msnobj --v and then track back two spaces to get the big number. Then everything between the e-mail address and the number is that other set of words, and you're good to go. -=-=- YouTube Twitter Computer Science Series: Logic (pt1) (part 2) (part 3) 2's Complement Mathematics: Basic Differential Calculus
Sun, 04 Jan 2009, 10:46
Afr0	How do I track backwards, though? I can't use string.Remove to start from the end of the string, can I? -=-=- Afr0 Games Project Dollhouse on Github - Please fork!
Sun, 04 Jan 2009, 12:01
Scherererer	I'm saying combine stuff like string.Substring(), string.IndexOf(), and string.LastIndexOf() -=-=- YouTube Twitter Computer Science Series: Logic (pt1) (part 2) (part 3) 2's Complement Mathematics: Basic Differential Calculus
Sun, 04 Jan 2009, 12:27
Afr0	That's what I've been doing, and can't figure it out!! :\ Edit: I changed Test() to this: private string Test(string StrData) { if(StrData.Contains("<msnobj")) { int Place = StrData.IndexOf("<msnobj"); StrData = StrData.Remove(Place, StrData.Length - Place); StrData.Replace("<msnobj", ""); } return StrData; } --v That's a good start. Now I just have to remove ClientID. Then I have to meditate on wtf happens if the server decides to not send an <msnobj> for some God-forsaken reason. -=-=- Afr0 Games Project Dollhouse on Github - Please fork!
Sun, 04 Jan 2009, 13:14
Phoenix	I'd just take the easy way out and use regular expressions. Always work perfectly when parsing text like this. To match this: 'ILN 5 NLN afr088@hotmail.com HELLO I ARE TEH c00lzorz!!11 454564' You could probably write two regexes (haven't tested these), and then capture the string between their first capture groups' indexes. 1. [^@]+[@a-zA-Z\.]\s(.) 2. (.)\s\d+$ These two regexes (should) match the parts outside of the name you want. So, assuming you're using C#'s standard System.Text.RegularExpressions functionality, you'd write something like this (also untested): Regex first = new Regex("[^@]+[@a-zA-Z\.]\s(.)"); Regex second = new Regex("(.)\s\d+$"); Match firstMatch = first.Match(yourStringHere); Match secondMatch = second.Match(yourStringHere); string name = yourStringHere.Substring(firstMatch.Groups[1].Index, secondMatch.Groups[1].Index); --v There's probably an easier way, but tell me if it works Don't really have access to a real computer (stupid Macintosh...) so I can't test.
Sun, 04 Jan 2009, 21:18
Afr0	//We've hit an ILN command, not a MSG command (email notification)! if (ILN.Contains("ILN")) { int Place = 0; string DecodedILN = HttpUtility.UrlDecode(ILN, Encoding.UTF8); string[] Params = DecodedILN.Split(' '); string Command = Params[0]; //Actual ILN command. string TransactionID = Params[1]; string StatusCode = Params[2]; string AccountName = Params[3]; //Place in string of DisplayName. //Add 3 to the end to account for spaces. Place = StatusCode.Length + AccountName.Length + Command.Length + TransactionID.Length + 3; string DisplayName = DecodedILN.Remove(0, Place); //DisplayName = Test(DisplayName);*/ Regex first = new Regex(@"[^@]+[@a-zA-Z\.]\s(.)"); Regex second = new Regex(@"(.)\s\d+$"); Match firstMatch = first.Match(DisplayName); Match secondMatch = second.Match(DisplayName); string name = DisplayName.Substring(firstMatch.Groups[1].Index, secondMatch.Groups[1].Index); MessageBox.Show(name); --v I did like this. It didn't work. I also tried to search within DecodedILN. It didn't work either! But I think you're right - regular expressions are the way to go. -=-=- Afr0 Games Project Dollhouse on Github - Please fork!
Mon, 05 Jan 2009, 04:56
Phoenix	Well I actually meant that you should just insert the whole string in there, not just the part after the email address. But if you can trim it down to that part then you only need the second regex. I modified your code: //We've hit an ILN command, not a MSG command (email notification)! if (ILN.Contains("ILN")) { int Place = 0; string DecodedILN = HttpUtility.UrlDecode(ILN, Encoding.UTF8); string[] Params = DecodedILN.Split(' '); string Command = Params[0]; //Actual ILN command. string TransactionID = Params[1]; string StatusCode = Params[2]; string AccountName = Params[3]; //Place in string of DisplayName. //Add 3 to the end to account for spaces. Place = StatusCode.Length + AccountName.Length + Command.Length + TransactionID.Length + 3; string DisplayName = DecodedILN.Remove(0, Place); //DisplayName = Test(DisplayName);*/ Regex second = new Regex("(.)\s\d+$"); Match secondMatch = second.Match(DisplayName); string name = DisplayName.Substring(0, secondMatch.Groups[1].Index); MessageBox.Show(name); --v
Mon, 05 Jan 2009, 12:57
Afr0	Bah. Regex didn't work, and I couldn't figure out how to get any matches, even though I downloaded RegexBuddy. Thus, I made this hackery: /// <summary> /// Helper function for getting DisplayName and ClientID /// from an ILN command. Ugly hack! Could probably be /// made faster. /// </summary> /// <param name="StrData">Data to get DisplayName and ClientID from. /// Assumed to be in the form 'DisplayName ClientID (MSNObj)</param> /// <returns>DisplayName and ClientID in a string-array.</returns> private string[] GetDisplayNameAndClientID(string StrData) { string[] ReturnStrs = new string[] { "", "" }; string DisplayName = ""; string ClientID = ""; if (StrData.Contains("<msnobj")) { int Place = StrData.IndexOf("<msnobj"); StrData = StrData.Remove(Place, StrData.Length - Place); StrData = StrData.Replace("<msnobj", "").Trim(); string[] TmpArray = StrData.Split(' '); for (int i = 0; i <= TmpArray.Length - 2; i++) DisplayName = DisplayName + " " + TmpArray[i]; ClientID = TmpArray[TmpArray.Length - 1]; ReturnStrs[0] = DisplayName; ReturnStrs[1] = ClientID; } else { StrData.Trim(); string[] TmpArray = StrData.Split(' '); for (int i = 0; i <= TmpArray.Length - 3; i++) DisplayName = DisplayName + " " + TmpArray[i]; ClientID = TmpArray[TmpArray.Length - 2]; ReturnStrs[0] = DisplayName; ReturnStrs[1] = ClientID; } return ReturnStrs; } --v I'd still appreciate help, even if it's in the form of a Regex expression that actually works! Edit: Turns out, ILNs that don't contain an MSNObject have a trailing 0 at the end. Probably to indicate that there isn't an MSNObject. -=-=- Afr0 Games Project Dollhouse on Github - Please fork!
Mon, 05 Jan 2009, 13:31
Phoenix	It does work. I tried it two seconds ago. Removed dot to make it slightly shorter, but worked otherwise as well. string DisplayName = "HELLO I ARE TEH c00lzorz!!11 454564"; Regex second = new Regex(@"(\s)\d+$"); Match secondMatch = second.Match(DisplayName); string name = DisplayName.Substring(0, secondMatch.Groups[1].Index); Console.WriteLine(name); Console.ReadKey(); --v
Mon, 05 Jan 2009, 13:50
Afr0	Well, I'll be...! o_O Didn't seem to work in my program! I guess I'll have to try and see if I can make it work tommorrow. Offtopic: void m_Socket_OnNewLogin(MSNContact NewContact, MSNObject Obj) { //Update the existing contact's data in the AllowList. foreach (MSNContactGroup Group in m_Allowlist) { for (int i = 0; i < Group.Contacts.Count; i++) { if (Group.Contacts[i].EMail.Equals(NewContact.EMail)) { Group.Contacts[i].DisplayName = NewContact.DisplayName; Group.Contacts[i].StatusCode = NewContact.StatusCode; if (Obj != null) Group.Contacts[i].DisplayPicture = NewContact.DisplayPicture; } } } } --v w00t! Presence changes underway! -=-=- Afr0 Games Project Dollhouse on Github - Please fork!